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화학반응공학 2판 솔루션

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the engineering of chemical reactions , schmidt , 2nd edition
1장~12장 / 화학반응공학 2판 솔루션
the engineering of chemical reactions , schmidt , 2nd edition
1장~12장 / 화학반응공학 2판 솔루션


Semiconductor Physics and Devices: Basic Principles, 3rd edition Solutions Manual

Chapter 1 Problem Solutions

Chapter 1
Problem Solutions
1.1 (a) fcc: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms Total of 4 atoms per unit cell (b) bcc: 8 corner atoms × 1/8 = 1 atom 1 enclosed atom = 1 atom Total of 2 atoms per unit cell (c) Diamond: 8 corner atoms × 1/8 = 1 atom 6 face atoms × ½ = 3 atoms 4 enclosed atoms = 4 atoms Total of 8 atoms per unit cell 1.2 (a) 4 Ga atoms per unit cell Density = 4 atoms per cell, so atom vol. = 4 Then 4 Ratio =

FG 4πr IJ H3K
3

16 2 r (c) Body-centered cubic lattice 4 d = 4r = a 3 ⇒ a = r 3 Unit cell vol. = a =
3

FG 4πr IJ H 3…(생략)

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화학반응공학   2판   solution