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사이플러스 일반화학 7판 솔루션

등록일 : 2011-12-31
갱신일 : 2011-12-31


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[솔루션] 일반화학 7판 솔루션(사이플러스) 입니다.

총 1장부터 22장까지의 솔루션이 있습니다.

기초과학인 일반화학 수업을 듣기 위한 솔루션입니다.
1장의 솔루션 부분을 발췌했습니다..^^ 확인해보세용~

1. Introduction

Since 0.749 is a number less than one, n is a negative integer. In this case, n  1.

Combining the above two steps:
0.749  7.49  101

(b) Express 802.6 in scientific notation.

Solution: The decimal point must be moved two places to give N, a number between 1 and 10. In this case,

N  8.026

Since 802.6 is a number greater than one, n is a positive integer. In this case, n  2.

Combining the above two steps:
802.6  8.026  102

(c) Express 0.000000621 in scientific notation.

Solution: The decimal point must be moved seven places to give N, a number between 1 and 10. In this case,
N  6.21

Since 0.000000621 is a number less than one, n is a negative integer. In this case, n  7.

Combining the above two steps:
0.000000621  6.21  107

1.23 (a) 15,200 (b) 0.0000000778

1.24 (a) Express 3.256  105 in nonscientific notation.

For the above number expressed in scientific notation, n  5. To convert to nonscientific notation, the decimal point must be moved 5 places to the left.

3.256  105  0.00003256

(b) Express 6.03  106 in nonscientific notation.

For the above number expressed in scientific notation, n  6. The decimal place must be moved 6 places to the right to convert to nonscientific notation.

6.03  106  6,030,000

1.25 (a) 145.75  (2.3  101)  145.75  0.23  1.4598  102

(b)

(c) (7.0  103)  (8.0  104)  (7.0  103)  (0.80  103)  6.2  103

(d) (1.0  104)  (9.9  106)  9.9  1010

1.26 (a) Addition using scientific notation.

Strategy: Lets express scientific notation as N  10n. When adding numbers using scientific notation, we must write each quantity with the same exponent, n. We can then add the N parts of the numbers, keeping the exponent, n, the same.

Solution: Write each quantity with the same exponent, n.

Lets write 0.0095 in such a way that n  3. We have decreased 10n by 103, so we must increase N by 103. Move the decimal point 3 places to the right.

0.0095  9.5  103

Add the N parts of the numbers, keeping the exponent, n, the same.

9.5  103
 8.5  103
18.0  103

The usual practice is to express N as a number between 1 and 10. Since we must decrease N by a factor of 10 to express N between 1 and 10 (1.8), we must increase 10n by a factor of 10. The exponent, n, is increased by 1 from 3 to 2.

18.0  103  1.8  102

(b) Division using scientific notation.

Strategy: Lets express scientific notation as N  10n. When dividing numbers using scientific notation, divide the N parts of the numbers in the usual way. To come up with the correct exponent, n, we subtract the exponents.

Solution: Make sure that all numbers are expressed in scientific notation.

653  6.53  102

Divide the N parts of the numbers in the usual way.

6.53  5.75  1.14

Subtract the exponents, n.

1.14  102  (8)  1.14  102  8  1.14  1010

(c) Subtraction using scientific notation.

Strategy: Lets express scientific notation as N  10n. When subtracting numbers using scientific notation, we must write each quantity with the same exponent, n. We can then subtract the N parts of the numbers, keeping the exponent, n, the same.

Solution: Write each quantity with the same exponent, n.

Lets write 850,000 in such a way that n  5. This means to move the decimal point five places to the left.

850,000  8.5  105
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